Head loss over 250' in K1 = 0.45'

Head loss over 250' in K2 = 4.55'

K1 must be x times K2 where:

x = 4.55 / 0.45 = 10.1

You can juggle the equation for Darcy's Law and Equivalent K (harmonic mean of K1 and K2) as much as you want, but you will only ever be able to determine the ratio of K1:K2 as 10.1:1.

With only heads for observations, K1 and K2 are completely correlated, that is, any combination of K1 and K2 with a 10.1:1 ratio will yield the same head distribution. Knowing more values of head will not improve your plight.